Applying the Pythagorean theorem to a right triangle with legs 3 and 4 yields a hypotenuse of:

Prepare for the Pearson Revel Test with multiple-choice questions and detailed explanations. Ace your exam with confidence!

Multiple Choice

Applying the Pythagorean theorem to a right triangle with legs 3 and 4 yields a hypotenuse of:

Explanation:
In a right triangle, the square of the hypotenuse equals the sum of the squares of the two legs. So with legs 3 and 4, the hypotenuse length c satisfies c^2 = 3^2 + 4^2 = 9 + 16 = 25. Therefore c = sqrt(25) = 5. This is a familiar Pythagorean triple, so the numbers line up neatly. Other candidate lengths wouldn’t fit the relationship: a hypothetical hypotenuse of 3 would give c^2 = 9, not 25; 4 would give c^2 = 16; 6 would give c^2 = 36. Only 5 makes c^2 equal 25, matching the sum of the squares of the legs.

In a right triangle, the square of the hypotenuse equals the sum of the squares of the two legs. So with legs 3 and 4, the hypotenuse length c satisfies c^2 = 3^2 + 4^2 = 9 + 16 = 25. Therefore c = sqrt(25) = 5. This is a familiar Pythagorean triple, so the numbers line up neatly.

Other candidate lengths wouldn’t fit the relationship: a hypothetical hypotenuse of 3 would give c^2 = 9, not 25; 4 would give c^2 = 16; 6 would give c^2 = 36. Only 5 makes c^2 equal 25, matching the sum of the squares of the legs.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy